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Quiz 65

Anonymous
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description:

There is a sequence point after the initalization of each base and member, thus the code is well-formed and defined

#include <iostream>
struct Foo
{
Foo(int n) : x(n++), y(n++), z(n++) {}
int x;
int y;
int z;
};
int main(int argc, char** argv)
{
Foo f(3);
std::cout << "x: " << f.x << std::endl;
std::cout << "y: " << f.y << std::endl;
std::cout << "z: " << f.z << std::endl;
return 0;
}
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